\[\boxed{\text{20\ (20).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[x\] | \[- 2\] | \[- 1\] | \[0\] | \[1\] | \[2\] | \[4\] | \[5\] |
---|---|---|---|---|---|---|---|
\[3x - 1\] | \[- 7\] | \[- 4\] | \[- 1\] | \[2\] | \[5\] | \[11\] | \[14\] |
\[- 3x + 1\] | \[7\] | \[4\] | \[1\] | \[- 2\] | \[- 5\] | \[- 11\] | \[- 14\] |
\[\ 3 \cdot ( - 2) - \ 1\ = \ - 6\ - \ 1\ = \ - 7\]
\[\ 3 \cdot ( - 1) - \ 1\ = \ - 3\ - \ 1\ = \ - 4\]
\[\ 3 \cdot 0\ - \ 1\ = \ 0\ - \ 1\ = \ - 1\]
\[\ 3 \cdot 1\ - \ 1\ = \ 3\ - \ 1\ = \ 2\]
\[\ 3 \cdot 2\ - \ 1\ = \ 6\ - \ 1\ = \ 5\]
\[\ 3 \cdot 4\ - \ 1\ = \ 12\ - \ 1\ = \ 11\]
\[\ 3 \cdot 5\ - \ 1\ = \ 15\ - \ 1\ = \ 14\]
\[- 3\ \cdot ( - 2) + \ 1\ = \ 6\ + \ 1\ = \ 7\]
\[- 3 \cdot \ ( - 1) + \ 1\ = \ 3\ + \ 1\ = \ 4\]
\[- 3\ \cdot \ 0\ + \ 1\ = \ 0\ + \ 1\ = \ 1\]
\[- 3\ \cdot \ 1\ + \ 1\ = \ - 3\ + \ 1\ = \ - 2\]
\[- 3\ \cdot \ 2\ + \ 1\ = \ - 6\ + \ 1\ = \ - 5\]
\[- 3\ \cdot \ 4\ + \ 1\ = \ - 12\ + \ 1\ = \ - 11\]
\[- 3\ \cdot \ 5\ + \ 1\ = \ - 15\ + \ 1\ = \ - 14\]
\[Собственные\ значения\ \]
\[выражений\ \ (3x - 1)\ и\ \]
\[( - 3x + 1)\ являются\]
\[противоположными\ числами.\]