\[\boxed{\text{480\ (480).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[\textbf{а)}\ 25a^{4} \cdot \left( 3a^{3} \right)^{2} = 25a^{4} \cdot 9 \cdot a^{6} =\]
\[= 225a^{10}\]
\[\textbf{б)}\ \left( - 3b^{6} \right)^{4} \cdot b = ( - 3)^{4} \cdot b^{24} \cdot b =\]
\[= 81b^{25}\]
\[\textbf{в)}\ 8p^{15} \cdot ( - p)^{4} = 8p^{15} \cdot p^{4} =\]
\[= 8p^{19}\]
\[\textbf{г)}\ \left( - c^{2} \right)^{3} \cdot 0,15c^{4} =\]
\[= - c^{6} \cdot 0,15c^{4} = - 0,15c^{10}\]
\[\textbf{д)}\ \left( - 10c^{2} \right)^{4} \cdot 0,0001c^{11} =\]
\[= 10\ 000c^{8} \cdot 0,0001c^{11} = c^{19}\]
\[\textbf{е)}\ \left( 3b^{5} \right)^{2} \cdot \frac{2}{9}b^{3} = 9b^{10} \cdot \frac{2}{9}b^{3} =\]
\[= 2b^{13}\]
\[\textbf{ж)}\ \left( - 2x^{3} \right)^{2} \cdot \left( - \frac{1}{4}x^{4} \right) =\]
\[= 4x^{6} \cdot \left( - \frac{1}{4}x^{4} \right) = - x^{10}\]
\[\textbf{з)}\ \left( - \frac{1}{2}y^{4} \right)^{3} \cdot \left( - 16y^{2} \right) =\]
\[= - \frac{1}{8}y^{12} \cdot \left( - 16y^{2} \right) = 2y^{14}\ \]