ГДЗ по алгебре 7 класс Макарычев Задание 709

\[\boxed{\text{709\ (709).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[\textbf{а)}\ mx + my + 6x + 6y =\]

\[= (mx + my) + (6x + 6y) =\]

\[= m(x + y) + 6 \cdot (x + y) =\]

\[= (x + y)(m + 6)\]

\[\textbf{б)}\ 9x + ay + 9y + ax =\]

\[= (9a + 9y) + (ay + ax) =\]

\[= 9 \cdot (x + y) + a(x + y) =\]

\[= (x + y)(9 + a)\]

\[\textbf{в)}7a - 7b + an - bn =\]

\[= (7a - 7b) + (an - bn) =\]

\[= 7 \cdot (a - b) + n(a - b) =\]

\[= (a - b)(7 + n)\]

\[\textbf{г)}\ ax + ay - x - y =\]

\[= (ax + ay) - 1 \cdot (x + y) =\]

\[= a(x + y) - (x + y) =\]

\[= (x + y)(a - 1)\]

\[\textbf{д)}\ 1 - bx - x + b =\]

\[= (1 - x) + (b - bx) =\]

\[= (1 - x) + b(1 - x) =\]

\[= (1 - x)(1 + b)\]

\[\textbf{е)}\ xy + 2y - 2x - 4 =\]

\[= (xy + 2y) - (2x + 4) =\]

\[= y(x + 2) - 2 \cdot (x + 2) =\]

\[= (x + 2)(y - 2)\]