\[\boxed{\text{187\ (187).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[y = \frac{8x - 7}{x} = \frac{8x}{x} - \frac{7}{x} = 8 - \frac{7}{x}\]
\[\frac{7}{x}\text{\ \ }должно\ быть\ целым \Longrightarrow\]
\[\Longrightarrow \left\{ \begin{matrix} \frac{7}{x} = 7\ \ \\ \frac{7}{x} = 1\ \ \ \\ \frac{7}{x} = - 1 \\ \frac{7}{x} = - 7 \\ \end{matrix} \right.\ \Longrightarrow \left\{ \begin{matrix} x = 1\ \ \\ x = 7\ \ \ \\ x = - 7 \\ x = - 1 \\ \end{matrix} \right.\ \]
\[y(1) = 8 - \frac{7}{1} = 1;\]
\[y(7) = 8 - \frac{7}{7} = 8 - 1 = 7;\]
\[y( - 7) = 8 + \frac{7}{7} = 8 + 1 = 9;\]
\[y( - 1) = 8 + \frac{7}{1} = 8 + 7 = 15;\]
\[Ответ:(1;1),\ (7;7),\ ( - 7;9),\ \]
\[( - 1;15).\]