Решите систему неравенств: x^2+x-6<=0; x>0.

Ответ:

\[\left\{ \begin{matrix} x^{2} + x - 6 \leq 0 \\ x > 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]

\[x^{2} + x - 6 = 0\]

\[x_{1} + x_{2} = - 1\ \ \ \ \ \ x_{1} = - 3\]

\[x_{1}x_{2} = - 6\ \ \ \ \ \ \ \ \ \ \ x_{2} = 2\]

\[Ответ:x \in (0;\ \ 2\rbrack.\]