Решение:

$$\frac{5}{6} - \frac{3}{22} = \frac{5 \cdot 11}{6 \cdot 11} - \frac{3 \cdot 3}{22 \cdot 3} = \frac{55}{66} - \frac{9}{66} = \frac{55-9}{66} = \frac{46}{66} = \frac{23}{33}$$
$$0,75 - (\frac{3}{16} + \frac{1}{24}) = 0,75 - (\frac{3 \cdot 3}{16 \cdot 3} + \frac{1 \cdot 2}{24 \cdot 2}) = 0,75 - (\frac{9}{48} + \frac{2}{48}) = 0,75 - \frac{11}{48} = \frac{3}{4} - \frac{11}{48} = \frac{3 \cdot 12}{4 \cdot 12} - \frac{11}{48} = \frac{36}{48} - \frac{11}{48} = \frac{36-11}{48} = \frac{25}{48}$$
$$\frac{9}{16} + (0,25 - \frac{5}{24}) = \frac{9}{16} + (\frac{1}{4} - \frac{5}{24}) = \frac{9}{16} + (\frac{1 \cdot 6}{4 \cdot 6} - \frac{5}{24}) = \frac{9}{16} + (\frac{6}{24} - \frac{5}{24}) = \frac{9}{16} + \frac{1}{24} = \frac{9 \cdot 3}{16 \cdot 3} + \frac{1 \cdot 2}{24 \cdot 2} = \frac{27}{48} + \frac{2}{48} = \frac{27+2}{48} = \frac{29}{48}$$
$$0,88 - \frac{2}{15} = \frac{88}{100} - \frac{2}{15} = \frac{22}{25} - \frac{2}{15} = \frac{22 \cdot 3}{25 \cdot 3} - \frac{2 \cdot 5}{15 \cdot 5} = \frac{66}{75} - \frac{10}{75} = \frac{66-10}{75} = \frac{56}{75}$$
$$(\frac{1}{6} + \frac{5}{18}) - (\frac{1}{18} + \frac{1}{24}) = (\frac{1 \cdot 3}{6 \cdot 3} + \frac{5}{18}) - (\frac{1 \cdot 4}{18 \cdot 4} + \frac{1 \cdot 3}{24 \cdot 3}) = (\frac{3}{18} + \frac{5}{18}) - (\frac{4}{72} + \frac{3}{72}) = \frac{8}{18} - \frac{7}{72} = \frac{8 \cdot 4}{18 \cdot 4} - \frac{7}{72} = \frac{32}{72} - \frac{7}{72} = \frac{32-7}{72} = \frac{25}{72}$$
$$4 - 2\frac{4}{7} = 4 - \frac{2 \cdot 7 + 4}{7} = 4 - \frac{14 + 4}{7} = 4 - \frac{18}{7} = \frac{4 \cdot 7}{7} - \frac{18}{7} = \frac{28}{7} - \frac{18}{7} = \frac{28 - 18}{7} = \frac{10}{7} = 1 \frac{3}{7}$$
$$2,5 + 1\frac{2}{3} - 3\frac{1}{6} = 2\frac{1}{2} + 1\frac{2}{3} - 3\frac{1}{6} = \frac{5}{2} + \frac{5}{3} - \frac{19}{6} = \frac{5 \cdot 3}{2 \cdot 3} + \frac{5 \cdot 2}{3 \cdot 2} - \frac{19}{6} = \frac{15}{6} + \frac{10}{6} - \frac{19}{6} = \frac{15+10-19}{6} = \frac{6}{6} = 1$$
$$0,36 - \frac{9}{75} + \frac{2}{15} = \frac{36}{100} - \frac{9}{75} + \frac{2}{15} = \frac{9}{25} - \frac{9}{75} + \frac{2}{15} = \frac{9 \cdot 3}{25 \cdot 3} - \frac{9}{75} + \frac{2 \cdot 5}{15 \cdot 5} = \frac{27}{75} - \frac{9}{75} + \frac{10}{75} = \frac{27 - 9 + 10}{75} = \frac{28}{75}$$
$$(\frac{1}{2} - \frac{1}{3}) - (\frac{1}{4} - \frac{1}{5}) = (\frac{1 \cdot 3}{2 \cdot 3} - \frac{1 \cdot 2}{3 \cdot 2}) - (\frac{1 \cdot 5}{4 \cdot 5} - \frac{1 \cdot 4}{5 \cdot 4}) = (\frac{3}{6} - \frac{2}{6}) - (\frac{5}{20} - \frac{4}{20}) = \frac{1}{6} - \frac{1}{20} = \frac{1 \cdot 10}{6 \cdot 10} - \frac{1 \cdot 3}{20 \cdot 3} = \frac{10}{60} - \frac{3}{60} = \frac{10 - 3}{60} = \frac{7}{60}$$
$$3\frac{2}{9} + 4\frac{1}{6} - 1\frac{8}{27} = \frac{29}{9} + \frac{25}{6} - \frac{35}{27} = \frac{29 \cdot 6}{9 \cdot 6} + \frac{25 \cdot 9}{6 \cdot 9} - \frac{35 \cdot 2}{27 \cdot 2} = \frac{174}{54} + \frac{225}{54} - \frac{70}{54} = \frac{174+225-70}{54} = \frac{329}{54} = 6\frac{5}{54}$$
$$11 - 6\frac{2}{3} - 3\frac{5}{7} = 11 - \frac{20}{3} - \frac{26}{7} = \frac{11 \cdot 21}{1 \cdot 21} - \frac{20 \cdot 7}{3 \cdot 7} - \frac{26 \cdot 3}{7 \cdot 3} = \frac{231}{21} - \frac{140}{21} - \frac{78}{21} = \frac{231 - 140 - 78}{21} = \frac{13}{21}$$
$$\frac{27}{75} + 0,32 - \frac{7}{15} = \frac{27}{75} + \frac{32}{100} - \frac{7}{15} = \frac{27}{75} + \frac{8}{25} - \frac{7}{15} = \frac{27}{75} + \frac{8 \cdot 3}{25 \cdot 3} - \frac{7 \cdot 5}{15 \cdot 5} = \frac{27}{75} + \frac{24}{75} - \frac{35}{75} = \frac{27+24-35}{75} = \frac{16}{75}$$
$$(\frac{1}{3} - \frac{1}{4}) - (\frac{1}{5} - \frac{1}{6}) = (\frac{1 \cdot 4}{3 \cdot 4} - \frac{1 \cdot 3}{4 \cdot 3}) - (\frac{1 \cdot 6}{5 \cdot 6} - \frac{1 \cdot 5}{6 \cdot 5}) = (\frac{4}{12} - \frac{3}{12}) - (\frac{6}{30} - \frac{5}{30}) = \frac{1}{12} - \frac{1}{30} = \frac{1 \cdot 5}{12 \cdot 5} - \frac{1 \cdot 2}{30 \cdot 2} = \frac{5}{60} - \frac{2}{60} = \frac{5-2}{60} = \frac{3}{60} = \frac{1}{20}$$
$$5\frac{7}{12} - 2\frac{4}{9} + 1\frac{5}{18} = \frac{67}{12} - \frac{22}{9} + \frac{23}{18} = \frac{67 \cdot 3}{12 \cdot 3} - \frac{22 \cdot 4}{9 \cdot 4} + \frac{23 \cdot 2}{18 \cdot 2} = \frac{201}{36} - \frac{88}{36} + \frac{46}{36} = \frac{201-88+46}{36} = \frac{159}{36} = \frac{53}{12} = 4\frac{5}{12}$$
$$10 - 3\frac{4}{5} - 5\frac{2}{3} = 10 - \frac{19}{5} - \frac{17}{3} = \frac{10 \cdot 15}{1 \cdot 15} - \frac{19 \cdot 3}{5 \cdot 3} - \frac{17 \cdot 5}{3 \cdot 5} = \frac{150}{15} - \frac{57}{15} - \frac{85}{15} = \frac{150-57-85}{15} = \frac{8}{15}$$
$$\frac{3}{4} \cdot \frac{8}{9} = \frac{3 \cdot 8}{4 \cdot 9} = \frac{24}{36} = \frac{2}{3}$$
$$1\frac{7}{8} \cdot 0,4 = \frac{15}{8} \cdot \frac{4}{10} = \frac{15 \cdot 4}{8 \cdot 10} = \frac{60}{80} = \frac{3}{4} = 0,75$$
$$1\frac{1}{3} \cdot \frac{3}{7} + \frac{4}{7} \cdot 1\frac{1}{3} = \frac{4}{3} \cdot \frac{3}{7} + \frac{4}{7} \cdot \frac{4}{3} = \frac{4 \cdot 3}{3 \cdot 7} + \frac{4 \cdot 4}{7 \cdot 3} = \frac{12}{21} + \frac{16}{21} = \frac{12+16}{21} = \frac{28}{21} = \frac{4}{3} = 1\frac{1}{3}$$
$$\frac{5}{7} \cdot \frac{21}{25} = \frac{5 \cdot 21}{7 \cdot 25} = \frac{105}{175} = \frac{3}{5}$$
$$2\frac{1}{12} \cdot 0,8 = \frac{25}{12} \cdot \frac{8}{10} = \frac{25 \cdot 8}{12 \cdot 10} = \frac{200}{120} = \frac{5}{3} = 1\frac{2}{3}$$
$$2\frac{1}{4} \cdot \frac{7}{9} + \frac{2}{9} \cdot 2\frac{1}{4} = \frac{9}{4} \cdot \frac{7}{9} + \frac{2}{9} \cdot \frac{9}{4} = \frac{9 \cdot 7}{4 \cdot 9} + \frac{2 \cdot 9}{9 \cdot 4} = \frac{63}{36} + \frac{18}{36} = \frac{63+18}{36} = \frac{81}{36} = \frac{9}{4} = 2\frac{1}{4}$$

Ответ: вычисления выше

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