\( 2\frac{13}{48} = \frac{2 \cdot 48 + 13}{48} = \frac{96 + 13}{48} = \frac{109}{48} \)
\( 2\frac{5}{12} = \frac{2 \cdot 12 + 5}{12} = \frac{24 + 5}{12} = \frac{29}{12} \)
\( 3\frac{3}{4} = \frac{3 \cdot 4 + 3}{4} = \frac{12 + 3}{4} = \frac{15}{4} \)
\( 9\frac{3}{4} = \frac{9 \cdot 4 + 3}{4} = \frac{36 + 3}{4} = \frac{39}{4} \)

\( \frac{109}{48} + \frac{29}{12} = \frac{109}{48} + \frac{29 \cdot 4}{12 \cdot 4} = \frac{109}{48} + \frac{116}{48} = \frac{109 + 116}{48} = \frac{225}{48} \)

\( \frac{225}{48} : \frac{15}{4} = \frac{225}{48} \cdot \frac{4}{15} = \frac{225 \cdot 4}{48 \cdot 15} = \frac{(15 \cdot 15) \cdot 4}{(12 \cdot 4) \cdot 15} = \frac{15}{12} = \frac{5}{4} \)

\( \frac{39}{4} : 12 = \frac{39}{4} \cdot \frac{1}{12} = \frac{39}{48} = \frac{13}{16} \)

\( \frac{5}{4} - \frac{13}{16} = \frac{5 \cdot 4}{4 \cdot 4} - \frac{13}{16} = \frac{20}{16} - \frac{13}{16} = \frac{20 - 13}{16} = \frac{7}{16} \)

\( 8\frac{2}{19} = \frac{8 \cdot 19 + 2}{19} = \frac{152 + 2}{19} = \frac{154}{19} \)
\( 1\frac{10}{19} = \frac{1 \cdot 19 + 10}{19} = \frac{19 + 10}{19} = \frac{29}{19} \)
\( 1\frac{13}{15} = \frac{1 \cdot 15 + 13}{15} = \frac{15 + 13}{15} = \frac{28}{15} \)
\( 1\frac{6}{49} = \frac{1 \cdot 49 + 6}{49} = \frac{49 + 6}{49} = \frac{55}{49} \)
\( 3\frac{1}{12} = \frac{3 \cdot 12 + 1}{12} = \frac{36 + 1}{12} = \frac{37}{12} \)
\( 1\frac{25}{36} = \frac{1 \cdot 36 + 25}{36} = \frac{36 + 25}{36} = \frac{61}{36} \)

\( \frac{154}{19} : \frac{29}{19} = \frac{154}{19} \cdot \frac{19}{29} = \frac{154}{29} \)

\( \frac{28}{15} \cdot \frac{55}{49} = \frac{28 \cdot 55}{15 \cdot 49} = \frac{(4 \cdot 7) \cdot (5 \cdot 11)}{(3 \cdot 5) \cdot (7 \cdot 7)} = \frac{4 \cdot 11}{3 \cdot 7} = \frac{44}{21} \)

\( \frac{154}{29} - \frac{44}{21} = \frac{154 \cdot 21 - 44 \cdot 29}{29 \cdot 21} = \frac{3234 - 1276}{609} = \frac{1958}{609} \)
Примечание: \( 1958 = 2 \cdot 979 \), \( 609 = 3 \cdot 7 \cdot 29 \). Сократить нельзя.

\( \frac{37}{12} - \frac{61}{36} = \frac{37 \cdot 3}{12 \cdot 3} - \frac{61}{36} = \frac{111}{36} - \frac{61}{36} = \frac{111 - 61}{36} = \frac{50}{36} = \frac{25}{18} \)

\( \frac{1958}{609} : \frac{25}{18} = \frac{1958}{609} \cdot \frac{18}{25} = \frac{1958 \cdot 18}{609 \cdot 25} = \frac{(2 \cdot 979) \cdot (2 \cdot 3^2)}{(3 \cdot 7 \cdot 29) \cdot 5^2} = \frac{35244}{15225} \)
Можно заметить, что \( 1958 = 2 \cdot 979 \) и \( 609 = 3 \cdot 7 \cdot 29 \). \( 1958 \) и \( 609 \) не сокращаются. \( 18 = 2 \cdot 3^2 \) и \( 25 = 5^2 \).
\( \frac{1958}{609} \cdot \frac{18}{25} = \frac{1958 \cdot 18}{609 \cdot 25} = \frac{35244}{15225} \)
Сократим \( 18 \) и \( 609 \) на \( 3 \): \( \frac{1958}{203} \cdot \frac{6}{25} \).
\( 1958 \cdot 6 = 11748 \)
\( 203 \cdot 25 = 5075 \)
\( \frac{11748}{5075} \)

Ответ: 1) \( \frac{7}{16} \); 2) \( \frac{11748}{5075} \).

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