а) \(\frac{1}{2}+\frac{1}{3}+\frac{1}{5}=\frac{15}{30}+\frac{10}{30}+\frac{6}{30}=\frac{31}{30}=1\frac{1}{30}\).

б) \(\frac{1}{3}+\frac{3}{4}+\frac{5}{12}=\frac{4}{12}+\frac{9}{12}+\frac{5}{12}=\frac{18}{12}=1\frac{1}{2}\).

в) \(\frac{3}{5}+\frac{5}{6}+\frac{1}{2}=\frac{18}{30}+\frac{25}{30}+\frac{15}{30}=\frac{58}{30}=1\frac{14}{15}\).

а) \(\frac{1}{3}-\frac{1}{5}-\frac{1}{15}=\frac{5}{15}-\frac{3}{15}-\frac{1}{15}=\frac{1}{15}\).

б) \(\frac{1}{2}-\frac{2}{5}-\frac{1}{10}=\frac{5}{10}-\frac{4}{10}-\frac{1}{10}=0\).

в) \(\frac{7}{8}-\frac{1}{4}-\frac{1}{2}=\frac{7}{8}-\frac{2}{8}-\frac{4}{8}=\frac{1}{8}\).

а) \(3\frac{1}{3}+2\frac{1}{6}=5+\frac{2}{6}+\frac{1}{6}=5\frac{1}{2}\).

б) \(\frac{3}{5}+4\frac{1}{2}=4+\frac{6}{10}+\frac{5}{10}=5\frac{1}{10}\).

в) \(1\frac{3}{7}+2\frac{1}{2}=3+\frac{6}{14}+\frac{7}{14}=3\frac{13}{14}\).

а) \(1\frac{1}{8}-\frac{3}{4}=1\frac{1}{8}-\frac{6}{8}=\frac{3}{8}\).

б) \(1\frac{3}{5}-\frac{2}{3}=1+\frac{9}{15}-\frac{10}{15}=\frac{14}{15}\).

в) \(2\frac{1}{6}-1\frac{3}{4}=\frac{13}{6}-\frac{7}{4}=\frac{26}{12}-\frac{21}{12}=\frac{5}{12}\).

Ответ: 1) а) \(1\frac{1}{30}\); б) \(1\frac{1}{2}\); в) \(1\frac{14}{15}\). 2) а) \(\frac{1}{15}\); б) 0; в) \(\frac{1}{8}\). 3) а) \(5\frac{1}{2}\); б) \(5\frac{1}{10}\); в) \(3\frac{13}{14}\). 4) а) \(\frac{3}{8}\); б) \(\frac{14}{15}\); в) \(\frac{5}{12}\).

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