Преобразуем смешанное число: \(1\frac{19}{29}=\frac{48}{29}\). Тогда \(\frac{48}{29}\cdot\frac{7}{48}=\frac{7}{29}\).
\(1\frac{13}{58}=\frac{71}{58}\), поэтому \(\frac{71}{58}\cdot\frac{9}{71}=\frac{9}{58}\).
\(1\frac{15}{34}=\frac{49}{34}\), поэтому \(\frac{49}{34}\cdot\frac{17}{49}=\frac{17}{34}=\frac{1}{2}\).
\(1\frac{11}{45}=\frac{56}{45}\), поэтому \(\frac{56}{45}\cdot\frac{25}{56}=\frac{25}{45}=\frac{5}{9}\).
\(\frac{7}{12}:2\frac{1}{4}=\frac{7}{12}:\frac{9}{4}=\frac{7}{12}\cdot\frac{4}{9}=\frac{7}{27}\).
\(\frac{9}{14}:1\frac{4}{7}=\frac{9}{14}:\frac{11}{7}=\frac{9}{14}\cdot\frac{7}{11}=\frac{9}{22}\).
\(\frac{8}{11}:2\frac{2}{5}=\frac{8}{11}:\frac{12}{5}=\frac{8}{11}\cdot\frac{5}{12}=\frac{10}{33}\).
\(\frac{6}{13}:1\frac{1}{8}=\frac{6}{13}:\frac{9}{8}=\frac{6}{13}\cdot\frac{8}{9}=\frac{16}{39}\).
Сначала выполняем умножение: \(\frac{1}{15}+4\frac{4}{5}\cdot\frac{2}{21}=\frac{1}{15}+\frac{24}{5}\cdot\frac{2}{21}=\frac{1}{15}+\frac{16}{35}=\frac{11}{21}\).
\(\frac{3}{20}+3\frac{3}{4}\cdot\frac{1}{27}=\frac{3}{20}+\frac{15}{4}\cdot\frac{1}{27}=\frac{3}{20}+\frac{5}{36}=\frac{13}{45}\).
\(\frac{1}{14}+2\frac{1}{12}\cdot\frac{2}{15}=\frac{1}{14}+\frac{25}{12}\cdot\frac{2}{15}=\frac{1}{14}+\frac{5}{18}=\frac{22}{63}\).
\(\frac{10}{21}+2\frac{2}{15}\cdot\frac{3}{14}=\frac{10}{21}+\frac{32}{15}\cdot\frac{3}{14}=\frac{10}{21}+\frac{16}{35}=\frac{14}{15}\).

Ответ: 1) \(\frac{7}{29}\); 2) \(\frac{9}{58}\); 3) \(\frac{1}{2}\); 4) \(\frac{5}{9}\); 5) \(\frac{7}{27}\); 6) \(\frac{9}{22}\); 7) \(\frac{10}{33}\); 8) \(\frac{16}{39}\); 9) \(\frac{11}{21}\); 10) \(\frac{13}{45}\); 11) \(\frac{22}{63}\); 12) \(\frac{14}{15}\).

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