ГДЗ по алгебре 7 класс Макарычев Задание 127

\[\boxed{\text{127\ (127).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ \frac{1}{3}x = 12\]

\[x = 12\ :\frac{1}{3}\]

\[x = 12 \cdot 3\]

\[x = 36\]

\[Ответ:x = 36.\]

\[\textbf{б)}\ \frac{2}{3}y = 9\]

\[y = 9\ :\frac{2}{3}\]

\[y = 9 \cdot \frac{3}{2} = \frac{27}{2}\]

\[y = 13,5\]

\[Ответ:y = 13,5.\]

\[\textbf{в)} - 4x = \frac{1}{7}\]

\[x = \frac{1}{7}\ :( - 4)\]

\[x = - \frac{1}{7} \cdot \frac{1}{4}\]

\[x = - \frac{1}{28}\]

\[Ответ:x = - \frac{1}{28}.\]

\[\textbf{г)}\ 5y = - \frac{5}{8}\]

\[y = - \frac{5}{8}\ :5\]

\[y = - \frac{5}{8} \cdot \frac{1}{5}\]

\[y = - \frac{1}{8}\]

\[Ответ:y = - \frac{1}{8}.\]

\[\textbf{д)}\ \frac{1}{6}y = \frac{1}{3}\]

\[y = \frac{1}{3}\ :\frac{1}{6}\]

\[y = \frac{1}{3} \cdot 6\]

\[y = 2\]

\[Ответ:y = 2.\]

\[\textbf{е)}\ \frac{2}{7}x = 0\]

\[x = 0\ :\frac{2}{7}\]

\[x = 0\ \]

\[Ответ:x = 0.\]