ГДЗ по алгебре 7 класс Макарычев Задание 139

\[\boxed{\text{139\ (}\text{с}\text{).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)} - 5 < y < 2\]

\[\ y = - 4;\ - 3;\ - 2;\ - 1;0;1.\]

\[\textbf{б)}\ 28 \leq y \leq 31,2\]

\[y = 28;\ 29;30;31.\ \]

\[\boxed{\text{139\ (}\text{н}\text{).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ |x - 6| = 0\]

\[x - 6 = 0\]

\[x = 6.\]

\[Ответ:x = 6.\]

\[\textbf{б)}\ |x - 1| = 5\]

\[x - 1 = 5\ \ \ \ \ \ \ \ \ \ \ \ \ x - 1 = - 5\]

\[x = 5 + 1\ \ \ \ \ \ \ \ \ \ \ \ x = - 5 + 1\]

\[x = 6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = - 4\]

\[Ответ:x = - 4;\ \ x = 6.\]

\[\textbf{в)}\ 16 - 3|x| = 4\]

\[3|x| = 16 - 4\]

\[3|x| = 12\]

\[|x| = 12\ :3\]

\[|x| = 4\]

\[x = \pm 4.\]

\[Ответ:x = \pm 4.\]

\[\textbf{г)}\ 26 + 6|x| = 144\]

\[6|x| = 144 - 26\]

\[6|x| = 118\]

\[|x| = 118\ :6\]

\[|x| = \frac{118}{6} = \frac{59}{3} = 19\frac{2}{3}\]

\[x = \pm 19\frac{2}{3}\]

\[Ответ:x = \pm 19\frac{2}{3}.\]