ГДЗ по алгебре 7 класс Макарычев Задание 270

\[\boxed{\text{270\ (270).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[x = - 5 \Longrightarrow \ \ y = ( - 5)^{2} - 9 =\]

\[= 25 - 9 = 16.\]

\[x = 3 \Longrightarrow \ \ y = 3^{2} - 9 = 9 - 9 =\]

\[= 0.\]

\[x = - 3 \Longrightarrow y = ( - 3)^{2} - 9 =\]

\[= 9 - 9 = 0.\]

\[x = - 4 \Longrightarrow y = ( - 4)^{2} - 9 =\]

\[= 16 - 9 = 7.\]

\[x = 0 \Longrightarrow y = 0^{2} - 9 = - 9.\]

\[x = 2 \Longrightarrow y = 2^{2} - 9 = 4 - 9 =\]

\[= - 5.\]

\[x = 6 \Longrightarrow y = 6^{2} - 9 = 36 - 9 =\]

\[= 27.\]