\[\boxed{\text{473\ (473).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[\textbf{а)}\ \left( 2m^{3} \right)^{4} = 2^{4} \cdot m^{12} = 16m^{12}\]
\[\textbf{б)}\ (3a)^{2} = 9a^{2}\]
\[\textbf{в)}\ \left( - 0,6m^{3}n^{2} \right)^{3} =\]
\[= ( - 0,6)^{3} \cdot \left( m^{3} \right)^{3} \cdot \left( n^{2} \right)^{3} =\]
\[= - 0,216m^{9}n^{6}\]
\[\textbf{г)}\ \left( - 2xy^{3} \right)^{2} =\]
\[= ( - 2)^{2} \cdot x^{2} \cdot \left( y^{3} \right)^{2} = 4x^{2}y^{6}\]
\[\textbf{д)}\ \left( - xy^{4}b^{2} \right)^{4} =\]
\[= ( - x)^{4}\left( y^{4} \right)^{4}\left( b^{2} \right)^{4} = x^{4}y^{16}b^{8}\]
\[\textbf{е)}\ \left( - x^{2}y^{3}m \right)^{5} =\]
\[= \left( - x^{2} \right)^{5}\left( y^{3} \right)^{5} \cdot m^{5} =\]
\[= - x^{10}y^{15}m^{5}\ \]