ГДЗ по алгебре 7 класс Макарычев Задание 606

\[\boxed{\text{606\ (606).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ 8y - 3 - (5 - 2y) = 4,3\]

\[8y - 3 - 5 + 2y = 4,3\]

\[10y = 4,3 + 8\]

\[10y = 12,3\]

\[y = 12,3\ :10\]

\[y = 1,23\]

\[Ответ:y = 1,23.\]

\[\textbf{б)}\ 0,5y - 1 - (2y + 4) = y\]

\[0,5y - 1 - 2y - 4 - y = 0\]

\[- 2,5y = 5\]

\[y = 5\ :( - 2,5) = - 50\ :25\]

\[y = - 2\]

\[Ответ:y = - 2.\]

\[\textbf{в)} - 8x + (4 + 3x) = 10 - x\]

\[- 8x + 4 + 3x + x = 10\]

\[- 4x = 10 - 4\]

\[- 4x = 6\]

\[x = - \frac{6}{4} = - \frac{3}{2}\]

\[x = - 1,5\]

\[Ответ:x = - 1,5.\]

\[\textbf{г)}\ 1,3x - 2 - (3,3x + 5) = 2x + 1\]

\[1,3x - 2 - 3,3x - 5 - 2x = 1\]

\[- 4x = 1 + 7\]

\[- 4x = 8\]

\[x = 8\ :( - 4)\]

\[x = - 2\]

\[Ответ:x = - 2.\]