ГДЗ по алгебре 7 класс Макарычев Задание 632

\[\boxed{\text{632\ (632).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ 3 \cdot ( - 2x + 1) - 2 \cdot (x + 13) =\]

\[= 7x - 4 \cdot (1 - x)\]

\[- 6x + 3 - 2x - 26 =\]

\[= 7x - 4 + 4x\]

\[- 6x - 2x - 7x - 4x =\]

\[= 26 - 4 - 3\]

\[- 19x = 19\]

\[x = - 1\]

\[Ответ:x = - 1.\]

\[\textbf{б)} - 4 \cdot (5 - 2a) + 3 \cdot (a - 4) =\]

\[= 6 \cdot (2 - a) - 5a\]

\[- 20 + 8a + 3a - 12 =\]

\[= 12 - 6a - 5a\]

\[8a + 3a + 6a + 5a =\]

\[= 12 + 12 + 20\]

\[22a = 44\]

\[a = 2\]

\[Ответ:\ \ a = 2.\]

\[\textbf{в)}\ 3y(4y - 1) - 2y(6y - 5) =\]

\[= 9y - 8 \cdot (3 + y)\]

\[= 9y - 24 - 8y\]

\[- 3y + 10y - 9y + 8y = - 24\]

\[6y = - 24\]

\[y = - 4\]

\[Ответ:y = - 4.\]

\[\textbf{г)}\ 15x + 6x(2 - 3x) =\]

\[= 9x(5 - 2x) - 36\]

\[15x + 12x - 18x^{2} =\]

\[= 45x - 18x^{2} - 36\]

\[- 18x = - 36\]

\[x = 2\]

\[Ответ:x = 2.\]