ГДЗ по алгебре 7 класс Макарычев Задание 660

\[\boxed{\text{660\ (660).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ 3,28x - x^{2} = x(3,28 - x)\]

\[если\ x = 2,28:\ \]

\[2,28 \cdot (3,28 - 2,28) = 2,28 \cdot 1 =\]

\[= 2,28.\]

\[\textbf{б)}\ a^{2}y + a^{3} = a^{2}(y + a)\]

\[если\ a = - 1,5;\ \ y = - 8,5:\ \ \ \ \ \]

\[( - 1,5)^{2} \cdot ( - 8,5 - 1,5) =\]

\[= 2,25 \cdot ( - 10) = - 22,5.\]

\[\textbf{в)}\ ay^{2} - y^{3} = y^{2}(a - y)\]

\[если\ a = 8,8,\ \ y = - 1,2;\ \ \ \ \ \]

\[то\ \ ( - 1,2)^{2} \cdot \left( 8,8 - ( - 1,2) \right) =\]

\[= 1,44 \cdot 10 = 14,4.\]

\[\textbf{г)} - mb - m^{2} = - m(b + m)\]

\[если\ m = 3,48;\ \ b = 96,52:\ \ \ \ \]

\[- 3,48 \cdot (96,52 + 3,48) =\]

\[= - 3,48 \cdot 100 = - 348.\]