\[\boxed{\text{708\ (708).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[\textbf{а)}\ x(b + c) + 3b + 3c =\]
\[= x(b + c) + 3 \cdot (b + c) =\]
\[= (b + c)(x + 3)\]
\[\textbf{б)}\ y(a - c) + 5a - 5c =\]
\[= y(a - c) + 5 \cdot (a - c) =\]
\[= (a - c)(y + 5)\]
\[\textbf{в)}\ p(c - d) + c - d =\]
\[= p \cdot (c - d) + 1 \cdot (c - d) =\]
\[= (p + 1)(c - d)\]
\[\textbf{г)}\ a(p - q) + q - p =\]
\[= a \cdot (p - q) + 1 \cdot (a - q) =\]
\[= a(p - q) - (p - q) =\]
\[= (p - q)(a - 1)\ \]