ГДЗ по алгебре 7 класс Макарычев Задание 793

\[\boxed{\text{793\ (793).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[\textbf{а)}\ x^{2} - 10x + 24 =\]

\[= x^{2} - 6x - 4x + 24 =\]

\[= x(x - 6) - 4 \cdot (x - 6) =\]

\[= (x - 6)(x - 4)\]

\[\textbf{б)}\ x^{2} - 13x + 40 =\]

\[= x^{2} - 8x - 5x + 40 =\]

\[= x(x - 8) - 5 \cdot (x - 8) =\]

\[= (x - 8)(x - 5)\]

\[\textbf{в)}\ x^{2} + 8x + 7 =\]

\[= x^{2} + 7x + x + 7 =\]

\[= x(x + 7) + (x + 7) =\]

\[= (x + 7)(x + 1)\]

\[\textbf{г)}\ x^{2} + 15x + 54 =\]

\[= x^{2} + 9x + 6x + 54 =\]

\[= x(x + 9) + 6 \cdot (x + 9) =\]

\[= (x + 9)(x + 6)\]

\[\textbf{д)}\ x^{2} + x - 12 =\]

\[= x^{2} + 4x - 3x - 12 =\]

\[= x(x - 3) + 4 \cdot (x - 3) =\]

\[= (x - 3)(x + 4)\]

\[\textbf{е)}\ x^{2} - 2x - 35 =\]

\[= x^{2} - 7x + 5x - 35 =\]

\[= x(x - 7) + 5 \cdot (x - 7) =\]

\[= (x - 7)(x + 5)\ \]