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МатематикаГДЗ по алгебре 8 класс Макарычев ФГОС Задание 362
Задание 362
\[\boxed{\text{362\ (362).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[\textbf{а)}\ \sqrt{x} = 6 - x\]
\[\left\{ \begin{matrix} y = \sqrt{x}\text{\ \ \ \ } \\ y = 6 - x \\ \end{matrix} \right.\ \ \]
| \[x\] | \[0\] | \[1\] | \[4\] |
|---|---|---|---|
| \[y\] | \[0\] | \[1\] | \[2\] |
| \[x\] | \[0\] | \[1\] | \[4\] |
|---|---|---|---|
| \[y\] | \[6\] | \[5\] | \[2\] |
\[Ответ:x = 4.\]
\[\textbf{б)}\ \sqrt{x} = \frac{4}{x}\]
\[\left\{ \begin{matrix} y = \sqrt{x} \\ y = \frac{4}{x}\text{\ \ \ } \\ \end{matrix} \right.\ \]
| \[x\] | \[0\] | \[1\] | \[4\] |
|---|---|---|---|
| \[y\] | \[0\] | \[1\] | \[2\] |
| \[x\] | \[0\] | \[1\] | \[- 1\] | \[2\] | \[- 2\] | \[4\] | \[- 4\] |
|---|---|---|---|---|---|---|---|
| \[y\] | \[-\] | \[4\] | \[- 4\] | \[2\] | \[- 2\] | \[1\] | \[- 1\] |
\[Ответ:x \approx 2,5,\]
\[\textbf{в)} - x - 5 = \sqrt{x}\]
\[\left\{ \begin{matrix} y = - x - 5 \\ y = \sqrt{x}\text{\ \ \ \ \ \ \ \ } \\ \end{matrix} \right.\ \]
| \[x\] | \[0\] | \[- 5\] | \[- 2\] |
|---|---|---|---|
| \[y\] | \[- 5\] | \[0\] | \[- 3\] |
| \[x\] | \[0\] | \[1\] | \[4\] |
|---|---|---|---|
| \[y\] | \[0\] | \[1\] | \[2\] |
\[Ответ:общих\ точек\ нет.\]
\[\boxed{\text{362.}\text{\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]
Пояснение.
Решение.
\[\textbf{а)}\ \sqrt{100 \cdot 49} = 10 \cdot 7 = 70\]
\[\textbf{б)}\ \sqrt{81 \cdot 400} = 9 \cdot 20 = 180\]
\[\textbf{в)}\ \sqrt{64 \cdot 121} = 8 \cdot 11 = 88\]
\[\textbf{г)}\ \sqrt{144 \cdot 0,25} = 12 \cdot 0,5 = 6\]
\[\textbf{д)}\ \sqrt{0,01 \cdot 169} = 0,1 \cdot 13 = 1,3\]
\[\textbf{е)}\ \sqrt{2,25 \cdot 0,04} = 1,5 \cdot 0,2 = 0,3\]
