ГДЗ по математике 6 класс Мерзляк Задание 341

\[\boxed{\mathbf{341\ (341).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \left( \frac{11}{18} - \frac{4^{\backslash 2}}{9} \right) \cdot \frac{3}{16} =\]

\[= \left( \frac{11}{18} - \frac{8}{18} \right) \cdot \frac{3}{16} = \frac{3}{18} \cdot \frac{3}{16} =\]

\[= \frac{1}{6} \cdot \frac{3}{16} = \frac{3}{96} = \frac{1}{32}\]

\[3)\ 1\frac{3}{5} \cdot \left( \frac{3}{4} + 1\frac{3}{8} \right) =\]

\[= \frac{8}{5} \cdot \left( \frac{3^{\backslash 2}}{4} + \frac{11}{8} \right) = \frac{8}{5} \cdot \frac{6 + 11}{8} =\]

\[= \frac{8 \cdot 17}{5 \cdot 8} = \frac{17}{5} = 3\frac{2}{5}\]

\[= 13\frac{4}{5} - 12 = 1\frac{4}{5}\]

\[= \frac{12^{\backslash 2}}{5} - \frac{3}{10} = \frac{24 - 3}{10} = \frac{21}{10} =\]

\[= 2\frac{1}{10}\]

\[= \frac{35^{\backslash 2}}{6} + \frac{3^{\backslash 3}}{4} = \frac{70 + 9}{12} = \frac{79}{12} =\]

\[= 6\frac{7}{12}\]

\[8)\ \left( 8 - 2\frac{1}{7} \cdot 3\frac{1}{9} \right) \cdot \frac{27}{44} =\]

\[= \left( 8 - \frac{15}{7} \cdot \frac{28}{9} \right) \cdot \frac{27}{44} =\]

\[= \left( 8 - \frac{15 \cdot 28}{7 \cdot 9} \right) \cdot \frac{27}{44} =\]

\[9)\ \left( \frac{4}{5} + \frac{4}{7} \right) \cdot \left( 7\frac{11^{\backslash 3}}{12} - 5\frac{7^{\backslash 4}}{9} \right) =\]

\[= \frac{28 + 20}{35} \cdot \left( 7\frac{33}{36} - 5\frac{28}{36} \right) =\]

\[= \frac{48}{35} \cdot 2\frac{5}{36} =\]

\[10)\ \frac{4}{5} + \frac{4}{7} \cdot \left( 7\frac{11^{\backslash 3}}{12} - 5\frac{7^{\backslash 4}}{9} \right) =\]

\[= \frac{4}{5} + \frac{4}{7} \cdot \left( 7\frac{33}{36} - 5\frac{28}{36} \right) =\]

\[= \frac{4}{5} + \frac{4}{7} \cdot 2\frac{5}{36} =\]