1. Выполните действия:

\( \frac{1}{2} + \frac{1}{3} = \frac{3+2}{6} = \frac{5}{6} \)
\( \frac{1}{6} - \frac{1}{4} = \frac{2-3}{12} = -\frac{1}{12} \)
\( \frac{3}{4} + \frac{4}{7} = \frac{21+16}{28} = \frac{37}{28} = 1\frac{9}{28} \)
\( \frac{5}{9} - \frac{3}{8} = \frac{40-27}{72} = \frac{13}{72} \)
\( \frac{1}{6} + \frac{1}{12} = \frac{2+1}{12} = \frac{3}{12} = \frac{1}{4} \)
\( \frac{2}{3} - \frac{4}{27} = \frac{18-4}{27} = \frac{14}{27} \)
\( \frac{23}{25} + \frac{4}{5} = \frac{23+20}{25} = \frac{43}{25} = 1\frac{18}{25} \)
\( \frac{29}{60} - \frac{7}{30} = \frac{29-14}{60} = \frac{15}{60} = \frac{1}{4} \)
\( \frac{7}{9} + \frac{5}{12} = \frac{28+15}{36} = \frac{43}{36} = 1\frac{7}{36} \)
\( \frac{17}{20} + \frac{11}{15} = \frac{51+44}{60} = \frac{95}{60} = 1\frac{35}{60} = 1\frac{7}{12} \)
\( \frac{11}{12} - \frac{5}{18} = \frac{33-10}{36} = \frac{23}{36} \)
\( \frac{3}{8} + \frac{4}{5} = \frac{15+32}{40} = \frac{47}{40} = 1\frac{7}{40} \)
\( \frac{19}{21} - \frac{13}{15} = \frac{95-91}{105} = \frac{4}{105} \)
\( \frac{5}{6} - \frac{8}{15} = \frac{25-16}{30} = \frac{9}{30} = \frac{3}{10} \)
\( \frac{21}{22} - \frac{3}{55} = \frac{105-6}{110} = \frac{99}{110} = \frac{9}{10} \)

Ответ: 1) \(\frac{5}{6}\); 2) -\(\frac{1}{12}\); 3) \(1\frac{9}{28}\); 4) \(\frac{13}{72}\); 5) \(\frac{1}{4}\); 6) \(\frac{14}{27}\); 7) \(1\frac{18}{25}\); 8) \(\frac{1}{4}\); 9) \(1\frac{7}{36}\); 10) \(1\frac{7}{12}\); 11) \(\frac{23}{36}\); 12) \(1\frac{7}{40}\); 13) \(\frac{4}{105}\); 14) \(\frac{3}{10}\); 15) \(\frac{9}{10}\).

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