Ответ:
4. Преобразуйте смешанные числа по образцу:
Образец: \( 2 \frac{7}{9} = \frac{2 \cdot 9 + 7}{9} = \frac{18+7}{9} = \frac{25}{9} \)
- \( 8 \frac{5}{7} = \frac{8 \cdot 7 + 5}{7} = \frac{56+5}{7} = \frac{61}{7} \)
- \( 2 \frac{11}{17} = \frac{2 \cdot 17 + 11}{17} = \frac{34+11}{17} = \frac{45}{17} \)
- \( 7 \frac{3}{8} = \frac{7 \cdot 8 + 3}{8} = \frac{56+3}{8} = \frac{59}{8} \)
- \( 2 \frac{4}{101} = \frac{2 \cdot 101 + 4}{101} = \frac{202+4}{101} = \frac{206}{101} \)
- \( 1 \frac{4}{9} = \frac{1 \cdot 9 + 4}{9} = \frac{9+4}{9} = \frac{13}{9} \)
- \( 13 \frac{6}{17} = \frac{13 \cdot 17 + 6}{17} = \frac{221+6}{17} = \frac{227}{17} \)
- \( 5 \frac{1}{99} = \frac{5 \cdot 99 + 1}{99} = \frac{495+1}{99} = \frac{496}{99} \)
Ответ: 1) \(\frac{61}{7}\); 2) \(\frac{45}{17}\); 3) \(\frac{59}{8}\); 4) \(\frac{206}{101}\); 5) \(\frac{13}{9}\); 6) \(\frac{227}{17}\); 7) \(\frac{496}{99}\).
