ГДЗ по алгебре 8 класс Макарычев ФГОС Задание 1000

\[\boxed{\text{1000.\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]

\[\textbf{а)}\ \frac{\sqrt{12 - 25x}}{6}\]

\[\Longrightarrow 12 - 25x \geq 0\]

\[- 25x \geq - 12\]

\[x \leq \frac{12}{25}\]

\[x \leq 0,48\]

\[x \in ( - \infty;0,48\rbrack.\]

\[\textbf{б)}\ \frac{1}{\sqrt{5x - 11}}\]

\[\Longrightarrow 5x - 11 > 0\]

\[5x > 11\]

\[x > \frac{11}{5}\]

\[x > 2,2\]

\[x \in (2,2;\ + \infty).\]

\[\textbf{в)}\ \frac{4x}{\sqrt{(3x - 2)^{2}}}\]

\[\Longrightarrow 3x - 2 \neq 0\]

\[3x \neq 2\]

\[x \neq \frac{2}{3}\]

\[x \in \left( - \infty;\frac{2}{3} \right) \cup \left( \frac{2}{3};\ + \infty \right).\]