ГДЗ по алгебре 8 класс Макарычев ФГОС Задание 1178

\[\boxed{\text{1178.\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]

\[\textbf{а)}\ ( - 4)^{- 3} = \frac{1}{( - 4)^{3}} = - \frac{1}{64}\]

\[\textbf{б)}\ {2,5}^{- 1} = \left( \frac{5}{2} \right)^{- 1} = \frac{2}{5}\]

\[\textbf{в)}\ \left( - \frac{3}{4} \right)^{- 2} = \left( - \frac{4}{3} \right)^{2} = \frac{16}{9}\]

\[\textbf{г)}\ \left( 1\frac{1}{3} \right)^{- 3} = \left( \frac{4}{3} \right)^{- 3} =\]

\[= \left( \frac{3}{4} \right)^{3} = \frac{27}{64}\]

\[\textbf{д)} - {0,4}^{- 4} = - \left( \frac{2}{5} \right)^{- 4} =\]

\[= - \left( \frac{5}{2} \right)^{4} = - \frac{625}{16}\]

\[\textbf{е)} - \left( 2\frac{1}{2} \right)^{- 2} = - \left( \frac{5}{2} \right)^{- 2} =\]

\[= - \left( \frac{2}{5} \right)^{2} = - \frac{4}{25}\]