ГДЗ по алгебре 8 класс Макарычев ФГОС Задание 182

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\[y = \frac{120}{x}\ \]

\[\frac{120}{- 1200} = - \frac{1}{10} = - 0,1\]

\[\frac{120}{- 600} = - \frac{1}{5} = - 0,2\]

\[- 0,5 = \frac{120}{x}\]

\[x = \frac{120}{- 0,5} = - 120\ :\frac{1}{2} = - 240\]

\[- 1 = \frac{120}{x}\]

\[x = - \frac{120}{1} = - 120\]

\[\frac{120}{75} = \frac{24}{15} = \frac{8}{5} = \frac{16}{10} = 1,6\]

\[0,4 = \frac{120}{x}\]

\[x = \frac{120}{0,4}\]

\[x = 120\ :\frac{2}{5}\]

\[x = \frac{120 \cdot 5}{2}\]

\[x = 300\]