\[\boxed{\text{23.\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]
Пояснение.
Решение.
\[\textbf{а)}\text{\ x}^{2} - 25 = (x - 5) \cdot (x + 5)\]
\[\textbf{б)}\ 16 - c^{2} = (4 - c) \cdot (4 + c)\]
\[\textbf{в)}\ a^{2} - 6a + 9 = {(a - 3)}^{2}\]
\[\textbf{г)}\ x^{2} + 8x + 16 = {(x + 4)}^{2}\]
\[\textbf{д)}\ a^{3} - 8 = a^{3} - 2^{3} =\]
\[= (a - 2) \cdot (a^{2} + 2a + 4)\]
\[\textbf{е)}\text{\ b}^{3} + 27 = b^{3} + 3^{3} =\]
\[= (b + 3) \cdot (b^{2} - 3b + 9)\]