\[\boxed{\text{26.\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]
Пояснение.
Решение.
\[\textbf{а)}\frac{10\text{xz}}{15\text{yz}} = \frac{5z \cdot 2x}{5z \cdot 3y} = \frac{2x}{3y}\text{\ \ }\]
\[\textbf{б)}\frac{6ab^{2}}{9bc^{2}} = \frac{3b \cdot 2ab}{3b \cdot 3c²} = \frac{2ab}{3c^{2}}\]
\[\textbf{в)}\frac{2ay^{3}}{- 4a^{2}b} = - \frac{2a \cdot y^{3}}{2a \cdot 2ab} = - \frac{y^{3}}{2ab}\]
\[\textbf{г)}\frac{- 6p^{2}q}{- 2q^{3}} = \frac{2q \cdot 3p^{2}}{2q \cdot q²} = \frac{3p^{2}}{q^{2}}\]
\[\textbf{д)}\frac{24a^{2}c^{2}}{36ac} = \frac{12ac \cdot 2ac}{12ac \cdot 3} = \frac{2ac}{3}\]
\[\textbf{е)}\frac{63x^{2}y^{3}}{42x^{6}y^{4}} = \frac{21x^{2}y^{3} \cdot 3}{21x^{2}y^{3} \cdot 2x^{4}y} =\]
\[= \frac{3}{2x^{4}y}\]