ГДЗ по алгебре 8 класс Макарычев ФГОС Задание 408

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Пояснение.

Решение.

\[\textbf{а)}\frac{1}{3}\sqrt{351} < \frac{1}{2}\sqrt{188}\]

\[\sqrt{\frac{351}{9}} < \sqrt{\frac{188}{4}}\]

\[\sqrt{39} < \sqrt{47}\]

\[\textbf{б)}\frac{1}{3}\sqrt{54} = \frac{1}{5}\sqrt{150}\]

\[\sqrt{\frac{54}{9}} = \sqrt{\frac{150}{25}}\]

\[\sqrt{6} = \sqrt{6}\]

\[\textbf{в)}\ \sqrt{24} = \frac{1}{3}\sqrt{216}\]

\[\sqrt{24} = \sqrt{\frac{216}{9}}\]

\[\sqrt{24} = \sqrt{24}\]

\[\textbf{г)}\frac{2}{3}\sqrt{72} < 7\sqrt{\frac{2}{3}}\]

\[\sqrt{\frac{4 \cdot 72}{9}} < \sqrt{\frac{49 \cdot 2}{3}}\]

\[\sqrt{32} < \sqrt{32\frac{2}{3}}\]