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Пояснение.
Решение.
\[\textbf{а)}\ x^{2} + 16x + 63 = 0\]
\[\left\{ \begin{matrix} x_{1} + x_{2} = - 16 \\ x_{1}x_{2} = 63\ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\left\{ \begin{matrix} x_{1} = - 9 \\ x_{2} = - 7 \\ \end{matrix} \right.\ \]
\[\textbf{б)}\ z^{2} + 2z - 48 = 0\]
\[\left\{ \begin{matrix} z_{1} + z_{2} = - 2 \\ z_{1}z_{2} = - 48\ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\left\{ \begin{matrix} z_{1} = - 8 \\ z_{2} = 6\ \ \ \\ \end{matrix} \right.\ \]