\[\boxed{\text{784.}\text{\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]
\[Воспользуемся\ теоремой\]
\[\ Виета.\]
\[\textbf{а)}\ x = - 7;\ \ x = 2:\ \]
\[(x + 7)(x - 2) = x^{2} - 2x +\]
\[+ 7x - 14 = x^{2} + 5x - 14.\]
\[Трехчлен:\]
\[x^{2} + 5x - 14.\]
\[\textbf{б)}\ x = 3 - \sqrt{2};\ \ x = 3 + \sqrt{2}:\]
\[\left( x - \left( 3 - \sqrt{2} \right) \right)\left( x - \left( 3 + \sqrt{2} \right) \right) =\]
\[= \left( x - 3 + \sqrt{2} \right)\left( x - 3 - \sqrt{2} \right) =\]
\[= \left( (x - 3) + \sqrt{2} \right) \cdot\]
\[\cdot \left( (x - 3) - \sqrt{2} \right) =\]
\[= (x - 3)^{2} - \left( \sqrt{2} \right)^{2} =\]
\[= x^{2} - 6x + 9 - 2 =\]
\[= x^{2} - 6x + 7.\]
\[Трехчлен:\]
\[x^{2} - 6x + 7.\]