ГДЗ по алгебре 8 класс Макарычев ФГОС Задание 785

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\[2px^{2} - 2x - 2p - 3\]

\[при\ x = 0:\ \]

\[2p \cdot 0^{2} - 2 \cdot 0 - 2p - 3 = 0\]

\[- 2p - 3 = 0\]

\[2p = - 3\]

\[p = - 1,5.\]

\[\Longrightarrow 2 \cdot ( - 1,5)x^{2} - 2x -\]

\[- 2 \cdot ( - 1,5) - 3 = 0\]

\[- 3x^{2} - 2x = 0\]

\[3x^{2} + 2x = 0\]

\[x(3x + 2) = 0\]

\[x_{1} = 0;\ \ x_{2} = - \frac{2}{3}.\]

\[Ответ:при\ p = - 1,5;\ \ \]

\[x_{2} = - \frac{2}{3}.\]