\[\boxed{\text{79.\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]
Пояснение.
Решение.
\[\textbf{а)}\frac{2xy - 1^{\backslash 3}}{4x^{3}} - \frac{3y - x^{\backslash 2x}}{6x^{2}} =\]
\[= \frac{6xy - 3 - 6xy + 2x^{2}}{12x^{3}} =\]
\[= \frac{2x^{2} - 3}{12x^{3}}\]
\[\textbf{б)}\ \frac{1 - {b^{2}}^{\backslash 2b}}{3ab} + \frac{2b^{3} - 1}{6ab^{2}} =\]
\[= \frac{2b - 2b^{3} + 2b^{3} - 1}{6ab^{2}} =\]
\[= \frac{2b - 1}{6ab^{2}}\]
\[\textbf{в)}\ \frac{1^{\backslash 5a^{2}}}{3a^{3}} - \frac{2^{\backslash 3}}{5a^{5}} =\]
\[\textbf{г)}\ \frac{{b^{2}}^{\backslash x}}{6x^{5}} - \frac{b^{\backslash 2}}{3x^{6}} =\]