\[\ \boxed{\text{857.\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]
\[\frac{x^{2} - 6x + 3}{x + 2} = ?\text{\ \ \ \ \ \ }при\ x = - \frac{1}{3}\]
\[\frac{x^{2} - 6x + 9 - 6}{x + 2} =\]
\[= \frac{(x - 3)^{2} - 6}{x + 2} =\]
\[= \frac{\left( - \frac{1}{3} - 3 \right)^{2} - 6}{- \frac{1}{3} + 2\ } =\]
\[= \frac{\left( - 3\frac{1}{3} \right)^{2} - 6}{1\frac{2}{3}} =\]
\[= \frac{\left( - \frac{10}{3} \right)^{2} - 6}{\frac{5}{3}} =\]
\[= \left( \frac{100}{9} - 6 \right)\ :\frac{5}{3} = \frac{46}{9} \cdot \frac{3}{5} =\]
\[= \frac{46}{15} = 3\frac{1}{15}.\]