ГДЗ по алгебре 8 класс Макарычев ФГОС Задание 958

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\[\textbf{а)}\ \sqrt{2x - 4} \Longrightarrow\]

\[\Longrightarrow 2x - 4 \geq 0\]

\[2x \geq 4\]

\[x \geq 2\]

\[\textbf{б)}\ \sqrt{4 - 6a} \Longrightarrow\]

\[\Longrightarrow 4 - 6a \geq 0\]

\[- 6a \geq - 4\]

\[a \leq \frac{2}{3}\]

\[\textbf{в)}\ \sqrt{\frac{1 + 3a}{25}} \Longrightarrow\]

\[\Longrightarrow \ \frac{1 + 3a}{25} \geq 0\]

\[1 + 3a \geq 0\]

\[3a \geq - 1\]

\[a \geq - \frac{1}{3}\]

\[\textbf{г)}\sqrt{\frac{7 - 5a}{8}} \Longrightarrow\]

\[\Longrightarrow \frac{7 - 5a}{8} \geq 0\]

\[7 - 5a \geq 0\]

\[- 5a \geq - 7\]

\[a \leq \frac{7}{5}\]

\[a \leq 1,4\]

\[\textbf{д)}\ \sqrt{- 3 \cdot (1 - 5x)} \Longrightarrow\]

\[\Longrightarrow - 3 \cdot (1 - 5x) \geq 0\]

\[1 - 5x \leq 0\]

\[x \geq 0,2\]

\[\textbf{е)}\ \sqrt{- (6 - x)} \Longrightarrow\]

\[\Longrightarrow - (6 - x) \geq 0\]

\[6 - x \leq 0\]

\[x \geq 6\]