\[\boxed{\text{963.\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]
\[(k - 4)x^{2} + 16x - 24 = 0\]
\[Уравнение\ имеет\ 2\ корня\ \]
\[при\ D > 0.\]
\[D = b^{2} - 4ac,\ \ a = k - 4,\]
\[\ \ b = 16,\ \ c = - 24\]
\[16^{2} - 4 \cdot (k - 4) \cdot ( - 24) > 0\]
\[256 + 96 \cdot (k - 4) > 0\]
\[96k - 384 > - 256\]
\[96k > 128\]
\[k > \frac{128}{96}\]
\[k > \frac{4}{3}\]
\[Ответ:при\ \ k \in \left( 1\frac{1}{3};\ + \infty \right)\text{.\ }\]