ГДЗ по алгебре 8 класс Макарычев ФГОС Задание 993

\[\boxed{\text{993.\ }\text{еуроки}\text{-}\text{ответы}\text{\ }\text{на}\text{\ }\text{пятёрку}}\]

\[\textbf{а)} - 1 \leq 15x + 14 < 44\]

\[- 15 \leq 15x < 30\ \ \ \ |\ :15\]

\[- 1 \leq x < 2\]

\[\lbrack - 1;2)\]

\[\textbf{б)} - 1 \leq \frac{6 - a}{3} \leq 1\ \ \ | \cdot 3\]

\[- 3 \leq 6 - a \leq 3\]

\[- 9 \leq - a \leq - 3\ \ \ | \cdot ( - 1)\]

\[9 \geq a \geq 3\]

\[3 \leq a \leq 9\]

\[\lbrack 3;9\rbrack\]

\[\textbf{в)} - 1,2 < 1 - 2y < 2,4\]

\[- 2,2 < - 2y < 1,4\ \ \ |\ :( - 2)\]

\[1,1 > y > - 0,7\]

\[- 0,7 < y < 1,1\]

\[( - 0,7;1,1)\]

\[\textbf{г)} - 2 < \frac{4x - 1}{3} \leq 0\ \ \ \ \ | \cdot 3\]

\[- 6 < 4x - 1 \leq 0\]

\[- 5 < 4x \leq 1\ \ |\ :4\]

\[- \frac{5}{4} < x \leq \frac{1}{4}\]

\[\left( - \frac{5}{4};\frac{1}{4} \right\rbrack\]