ГДЗ по алгебре 9 класс Макарычев ФГОС Задание 164

\[\boxed{\text{165.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]

Пояснение.

\[\textbf{а)}\ (x - 1)^{2} + (x + 1)^{2} =\]

\[= (x + 2)^{2} - 2x + 2\]

\[x^{2} - 2x + 1 + x^{2} + 2x + 1 =\]

\[= x^{2} + 4x + 4 - 2x + 2\]

\[2x^{2} + 2 = x^{2} + 2x + 6\]

\[x² - 2x - 4 = 0\]

\[D = 1 + 4 = 5\]

\[x_{1,2} = 1 \pm \sqrt{5}.\]

\[Ответ:x = 1 \pm \sqrt{5}.\]

\[\textbf{б)}\ (2x - 3)(2x + 3) - 1 =\]

\[= 5x + (x - 2)²\]

\[4x^{2} - 9 - 1 = 5x + x^{2} - 4x + 4\]

\[3x^{2} - x - 14 = 0\]

\[D = 1 + 4 \cdot 3 \cdot 14 = 169\]

\[x_{1,2} = \frac{1 \pm 13}{6},\ \ \]

\[x_{1} = - 2,\ \ x_{2} = \frac{14}{6} = 2\frac{1}{3}.\]

\[Ответ:x = - 2;\ \ x = 2\frac{1}{3}.\]