ГДЗ по алгебре 9 класс Макарычев ФГОС Задание 190

\[\boxed{\text{191.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]

\[y = ax²\]

\[\textbf{а)}\ (5;\ - 7):\ \ \ \]

\[- 7 = a \cdot 5^{2}\]

\[- 7 = 25a\]

\[a = - \frac{7}{25}\]

\[Ответ:при\ a = - \frac{7}{25}.\]

\[\textbf{б)}\ \left( - \sqrt{3};9 \right):\ \ \]

\[9 = a \cdot \left( - \sqrt{3} \right)^{2}\]

\[9 = 3a\]

\[a = 3\]

\[Ответ:при\ a = 3.\]

\[\textbf{в)}\ \left( - \frac{1}{2};\ - \frac{1}{2} \right):\ \ \]

\[- \frac{1}{2} = a \cdot \left( - \frac{1}{2} \right)^{2}\]

\[- \frac{1}{2} = a \cdot \frac{1}{4}\]

\[a = - \frac{1}{2}\ :\frac{1}{4}\]

\[a = - 2\]

\[Ответ:при\ a = - 2.\]

\[\textbf{г)}\ (100;10):\]

\[10 = a \cdot 100^{2}\]

\[10 = 10\ 000a\]

\[a = \frac{10}{10000}\]

\[a = 0,001\]

\[Ответ:при\ a = 0,001.\]