ГДЗ по алгебре 9 класс Макарычев ФГОС Задание 234

\[\boxed{\text{235.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]

\[\textbf{а)}\ \frac{2}{x - 2} - \frac{10}{x + 3} = \frac{50}{x^{2} + x - 6} - 1\]

\[\frac{x^{2} - 7x - 30}{(x - 2)(x + 3)} = 0\]

\[\frac{(x - 10)(x + 3)}{(x - 2)(x + 3)} = 0\]

\[\frac{x - 10}{x - 2} = 0\]

\[x - 10 = 0\]

\[x = 10.\]

\[Ответ:x = 10.\]

\[\textbf{б)}\ \frac{x + 5}{x - 1} + \frac{2x - 5}{x - 7} - \frac{30 - 12x}{8x - x^{2} - 7} = 0\]

\[\frac{3x^{2} - 21x}{(x - 1)(x - 7)} = 0\]

\[\frac{3x(x - 7)}{(x - 1)(x - 7)} = 0\]

\[\frac{3x}{x - 1} = 0\]

\[3x = 0\]

\[x = 0.\]

\[Ответ:x = 0.\]