\[\boxed{\text{273.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]
\[\textbf{а)}\ 2x(3x - 1) > 4x² + 5x + 9\]
\[6x^{2} - 2x > 4x^{2} + 5x + 9\]
\[2x^{2} - 7x - 9 > 0\]
\[D = 49 + 4 \cdot 2 \cdot 9 = 121\]
\[x_{1,2} = \frac{7 \pm 11}{4},\ \ x_{1} = - 1,\]
\[\text{\ \ }x_{2} = 4,5.\]
\[2 \cdot (x + 1)(x - 4,5) > 0\]
\[x \in ( - \infty;\ - 1) \cup (4,5;\ + \infty).\]
\[\textbf{б)}(5x + 7)(x - 2) <\]
\[< 21x² - 11x - 13\]
\[5x^{2} - 10x + 7x - 14 <\]
\[< 21x^{2} - 11x - 13\]
\[16x^{2} - 8x + 1 > 0\]
\[(4x - 1)² > 0\ \]
\[x \in ( - \infty;0,25) \cup (0,25;\ + \infty).\]