ГДЗ по алгебре 9 класс Макарычев ФГОС Задание 273

\[\boxed{\text{274.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]

\[\textbf{а)}\ y = \sqrt{12x - 3x²}\]

\[12x - 3x^{2} \geq 0\]

\[x^{2} - 4x \leq 0\]

\[x(x - 4) \leq 0\]

\[x \in \lbrack 0;4\rbrack.\]

\[\textbf{б)}\ y = \frac{1}{\sqrt{2x^{2} - 12x + 18}}\]

\[2x^{2} - 12x + 18 > 0\]

\[x^{2} - 6x + 9 > 0\]

\[(x - 3)^{2} > 0\]

\[x \in ( - \infty;3) \cup (3;\ + \infty).\]