ГДЗ по алгебре 9 класс Макарычев ФГОС Задание 349

\[\boxed{\text{350.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]

\[\textbf{а)}\ (3x - 5)(x + 4)(2 - x) = 0\]

\[x_{1} = \frac{5}{3} = 1\frac{2}{3},\ \ x_{2} = - 4,\ \ \]

\[x_{3} = 2.\ \]

\[\textbf{б)}\ (3x - 5)(x + 4)(2 - x) > 0\]

\[\left( x - \frac{5}{3} \right)(x + 4)(x - 2) < 0\]

\[x \in ( - \infty;\ - 4) \cup \left( 1\frac{2}{3};2 \right).\]

\[\textbf{в)}\ (3x - 5)(x + 4)(2 - x) < 0\]

\[\left( x - \frac{5}{3} \right)(x + 4)(x - 2) > 0\]

\[x \in \left( - 4;1\frac{2}{3} \right) \cup (2; + \infty).\]