\(\boxed{\text{403.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\)
\[\textbf{а)}\ (x - 6)^{2} + (y + 4)^{2} = 4;\ \]
\[\ \ y = - 2\]
\[x^{2} - 12x + 36 + ( - 2 + 4)^{2} = 4\]
\[x^{2} - 12x + 36 + 4 - 4 = 0\]
\[x^{2} - 12x + 36 = 0\]
\[(x - 6)^{2} = 0\]
\[x = 6.\]
\[Одна\ точка\ пересечения.\]
\[\textbf{б)}\ (x - 3)^{2} + (y - 2)^{2} = 9;\ \ \]
\[x = 7\]
\[(7 - 3)^{2} + (y - 2)^{2} = 9\]
\[16 + y^{2} - 4y + 4 - 9 = 0\]
\[y^{2} - 4y + 11 = 0\]
\[D = 16 - 44 < 0\]
\[Нет\ точек\ пересечения.\]