\[\boxed{\text{524.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]
\[\textbf{а)}\ y\left( x^{2} + y^{2} - 1 \right) \geq 0\]
\[\textbf{б)}\ x\left( x^{2} - y \right) \leq 0\]