\[\boxed{\text{566.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]
\[\textbf{а)}\ x³ + 4x² - 32x = 0\]
\[x\left( x^{2} + 4x - 32 \right) = 0\]
\[1)\ x_{1} = 0;\]
\[2)\ x² + 4x - 32 = 0\ \ \]
\[по\ теореме\ Виета:\]
\[x_{2} = - 8,\ \ x_{3} = 4.\]
\[\textbf{б)}\ x³ - 10x^{2} + 4x - 40 = 0\]
\[x^{2}(x - 10) + 4 \cdot (x - 10) = 0\]
\[\left( x^{2} + 4 \right)(x - 10) = 0\]
\[x = 10.\]
\[Ответ:\ \ \ а) - 8;0;4;\ \ б)\ 10.\]