ГДЗ по геометрии 8 класс Атанасян ФГОС Задание 1107

\[\boxed{\mathbf{1107}.еуроки - ответы\ на\ пятёрку}\]

\[\textbf{а)}\ y = x + 1\]

\[k = tg\alpha = 1\]

\[\alpha = 45{^\circ}.\]

\[\textbf{б)}\ y = - x + 2\]

\[k = tg\alpha = - 1\]

\[\alpha = 135{^\circ}.\]

\[\textbf{в)}\ y = \frac{\sqrt{3}}{3}x + 4\]

\[k = tg\alpha = \frac{\sqrt{3}}{3}\]

\[\alpha = 30{^\circ}.\]

\[\textbf{г)}\ y = - \frac{\sqrt{3}}{3}x + 5\]

\[k = tg\ \alpha = - \frac{\sqrt{3}}{3}\]

\[\alpha = 150{^\circ}.\]

\[\textbf{д)}\ y = - \sqrt{3}x - 2\]

\[k = tg\alpha = - \sqrt{3}\]

\[\alpha = 120{^\circ}.\]