Вопрос:
1163.
1) [(6 1/6-1 1/24):(8 3/8+7,2)+418/623]:[(16/17-45/68)·17/20]
Смотреть решения всех заданий с листаОтвет:
Выполним вычисления:
- $$6\frac{1}{6} = \frac{37}{6}$$
- $$1\frac{1}{24} = \frac{25}{24}$$
- $$8\frac{3}{8} = \frac{67}{8}$$
- $$\frac{37}{6} - \frac{25}{24} = \frac{37 \cdot 4 - 25}{24} = \frac{148 - 25}{24} = \frac{123}{24} = \frac{41}{8}$$
- $$7,2 = \frac{72}{10} = \frac{36}{5}$$
- $$\frac{67}{8} + \frac{36}{5} = \frac{67 \cdot 5 + 36 \cdot 8}{40} = \frac{335 + 288}{40} = \frac{623}{40}$$
- $$\frac{41}{8} : \frac{623}{40} = \frac{41}{8} \cdot \frac{40}{623} = \frac{41}{1} \cdot \frac{5}{623} = \frac{205}{623}$$
- $$\frac{205}{623} + \frac{418}{623} = \frac{623}{623} = 1$$
- $$\frac{16}{17} - \frac{45}{68} = \frac{16 \cdot 4 - 45}{68} = \frac{64 - 45}{68} = \frac{19}{68}$$
- $$\frac{19}{68} \cdot \frac{17}{20} = \frac{19}{4} \cdot \frac{1}{20} = \frac{19}{80}$$
- $$1 : \frac{19}{80} = \frac{80}{19}$$
Ответ: 80/19
ГДЗ по фото 📸Похожие
- 1161. 1) (0,8-0,47) (0,8 +0,47)
0,4191
+
(1+3/5)·(1-3/5)
1,6
- 2) (4,5-3 2/7):(7 1/2:8 1/3+2 1/7:3-4 1/3+2·1 3/4)
- 1162.
1) (3 1/3·6,6+2:12,75): (2/3-51/20+1 16/17)+ 9 3/25·1 5/28
(75:4 1/6-3 9/23·3)·(5/18+0,35-11/15) + 1,25·5,6
- 2) 1/17·(2,5+3 1/3 : 2 1/2-1 1/3):(4 3/5 -2 1/3)·(0,25-0,2/1/7-0,125 -0,2)
- 2) [(7,85 +3,15)·1 2/5 : (7,2 : 2)]. (1/7 : 0,2)
- 1164. 1)
15,2·0,975 (4-1,15:0,5)·24
2,8:0,7-3/4 + 1/4·20+10:100
- 2) (2 11/15+1,6+1 7/12+1/3)·(3 5/14-2 19/30):1 3/7
(1/6+0,1+1/15):(1/6+0,1-1/15)
- 1165. 1)
(0,5-1/3+0,25-0,2):(0,25-1/6)
3 1/3-(6 1/7-5 3/4):5/7 +0,625:5/6
8+0,375:0,5625
- 2) 3 1/3-(6 1/7-5 3/4):5/7 +0,625:5/6
8+0,375:0,5625