1) \((\frac{5}{14}+\frac{17}{42})\cdot1\frac{6}{8}=(\frac{5\cdot3}{14\cdot3}+\frac{17}{42})\cdot1\frac{3}{4}=(\frac{15}{42}+\frac{17}{42})\cdot\frac{7}{4}=\frac{32}{42}\cdot\frac{7}{4}=\frac{16}{21}\cdot\frac{7}{4}=\frac{4}{3}=1\frac{1}{3}\)
2) \((5\frac{8}{9}:1\frac{17}{36}+1\frac{1}{4})\cdot\frac{5}{21}=(\frac{53}{9}:\frac{53}{36}+1\frac{1}{4})\cdot\frac{5}{21}=(\frac{53}{9}\cdot\frac{36}{53}+1\frac{1}{4})\cdot\frac{5}{21}=(4+1\frac{1}{4})\cdot\frac{5}{21}=5\frac{1}{4}\cdot\frac{5}{21}=\frac{21}{4}\cdot\frac{5}{21}=\frac{5}{4}=1\frac{1}{4}\)
Ответ: 1) \(1\frac{1}{3}\), 2) \(1\frac{1}{4}\)