5) $$3\frac{7}{19}\cdot(\frac{5}{12}+\frac{3}{8}):1\frac{1}{3}-1\frac{3}{8}:(1\frac{1}{5}-\frac{1}{4})$$ 6) $$(17:3\frac{2}{5}-6\frac{3}{8}:3\frac{3}{8}):(1\frac{1}{5}-\frac{29}{30})$$

Решение:

1. $$3\frac{7}{19} \cdot (\frac{5}{12} + \frac{3}{8}): 1\frac{1}{3} - 1\frac{3}{8} : (1\frac{1}{5} - \frac{1}{4}) = \frac{64}{19} \cdot (\frac{10}{24} + \frac{9}{24}) : \frac{4}{3} - \frac{11}{8} : (\frac{6}{5} - \frac{1}{4}) = \frac{64}{19} \cdot \frac{19}{24} : \frac{4}{3} - \frac{11}{8} : (\frac{24}{20} - \frac{5}{20}) = \frac{64}{19} \cdot \frac{19}{24} : \frac{4}{3} - \frac{11}{8} : \frac{19}{20} = \frac{64}{19} \cdot \frac{19}{24} \cdot \frac{3}{4} - \frac{11}{8} \cdot \frac{20}{19} = \frac{64 \cdot 19 \cdot 3}{19 \cdot 24 \cdot 4} - \frac{11 \cdot 20}{8 \cdot 19} = \frac{8 \cdot 1 \cdot 1}{1 \cdot 8 \cdot 4} - \frac{11 \cdot 5}{2 \cdot 19} = \frac{8}{4} - \frac{55}{38} = \frac{2}{1} - \frac{55}{38} = \frac{2 \cdot 38 - 55}{38} = \frac{76 - 55}{38} = \frac{21}{38}$$
2. $$(17:3\frac{2}{5} - 6\frac{3}{8} : 3\frac{3}{8}) : (1\frac{1}{5} - \frac{29}{30}) = (17 : \frac{17}{5} - \frac{51}{8} : \frac{27}{8}) : (\frac{6}{5} - \frac{29}{30}) = (17 \cdot \frac{5}{17} - \frac{51}{8} \cdot \frac{8}{27}) : (\frac{36}{30} - \frac{29}{30}) = (5 - \frac{51}{27}) : \frac{7}{30} = (5 - \frac{17}{9}) : \frac{7}{30} = (\frac{45}{9} - \frac{17}{9}) : \frac{7}{30} = \frac{28}{9} : \frac{7}{30} = \frac{28}{9} \cdot \frac{30}{7} = \frac{4 \cdot 10}{3 \cdot 1} = \frac{40}{3} = 13\frac{1}{3}$$

Ответ: 5) $$\frac{21}{38}$$, 6) $$13\frac{1}{3}$$