5\frac{1}{9}+11+4\frac{7}{18} 1\frac{2}{3}-0,4\cdot 3\frac{1}{3}

Выполним действия: $$5\frac{1}{9}+11+4\frac{7}{18} = \frac{46}{9} + 11 + \frac{79}{18} = \frac{92}{18} + \frac{198}{18} + \frac{79}{18} = \frac{92+198+79}{18} = \frac{369}{18} = \frac{41}{2} = 20\frac{1}{2}$$ $$1\frac{2}{3}-0,4\cdot 3\frac{1}{3}=\frac{5}{3} - \frac{4}{10} \cdot \frac{10}{3} = \frac{5}{3} - \frac{2}{5} \cdot \frac{5}{3} = \frac{5}{3} - \frac{2}{3} = \frac{3}{3} = 1$$ $$\frac{5\frac{1}{9}+11+4\frac{7}{18}}{1\frac{2}{3}-0,4\cdot 3\frac{1}{3}} = \frac{20\frac{1}{2}}{1} = 20\frac{1}{2} = 20,5$$ Ответ: 20,5